Y=a(1+r)^t 135272-Y=a(1+r)^t
Y = a(1 r)^t Example of Exponential Growth Equation y = 2500(105)^4 Example of Exponential Decay Equation y = 1(085)^6 Exponential Growth Graph Exponential Decay Graph Initial Value (yintercept) "a" in the function y = ab^x Compound Interest Formula A = P(1 r/n)^nt HalfLife Formula A = P(05)^t YOU MIGHT ALSO LIKEThe general equation for depreciation is given by y = a (1 – r)t, where y = current value, a = original cost, r = rate of depreciation, and t = time, in years the original value of a car is $24,000 it depreciates 15% annually what is its value in 4 years?I think you use the following formula y=a(1r)^t where y is the amount after t years, a is the initial amount, r is the annual growth rate, and t is the time in years I will appreciate everyones
The Angle Made By The Tangent Of The Curve X A T Si N Tcos T Y
Y=a(1+r)^t
Y=a(1+r)^t-Solve for t A=P(1r/n)^(nt) Rewrite the equation as Divide each term by and simplify Tap for more steps Divide each term in by Cancel the common factor of Tap for more steps Cancel the common factor Divide by Take the natural logarithm of both sides of the equation to remove the variable from the exponentExponential decay equation #1 – y = a (1 – r) t y = what's leftover a = what you start with r = rate t = time ex Timmy drank hot chocolate which has 110 milligrams of sugar If the sugar was eliminated from the body at a rate of 12% per hour
Remaining grams a = 16 Starting value r = 50% = 05 Decimal form b = 1 05 Decay Factor x = 500 5730 No of Half livesOf the polynomial are r = −1 and −4 The general solution is then y = C1 e −t C 2 e −4t Suppose there are initial conditions y(0) = 1, y′(0) = −7 A unique particular solution can be found by solving for C1 and C2 using the initial conditions First we need to calculate y′ = −C1 e −t − 4 C 2 e −4 t, then apply theThe general equation for depreciation is given by {eq}\displaystyle{ y = A(1 r)t }{/eq}, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years A car was
Answer 3 📌📌📌 question Rewrite the function in the form y=a(1r)^t of y=a(1r)^t Then state the growth of or decay rate Y=a(8)^t/2 the answers to estudyassistantcomAn equation for the depreciation of a car is given by y = A(1 – r)t, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The current value of a car is $12,250 The car originally cost $,000 and depreciates at a rate of 15% per year How old is the car?Hence, r = 1 = , or, rounding the value of "r" to the nearest tenthousandth, r = 0630 Therefore, your answer is y = 5*()^t It is EXACTLY the form you requested, with the value of r = 0630, rounded as it is assigned by the problem
Rewrite y=(14)^t8 in the form y=a(1r)^t I keep getting the wrong answer not sure if it goes to 4%?Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreAn equation for the depreciation of a car is given by y = A (1 – r)t, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The value of a car is half what it originally cost The rate of depreciation is 10% Approximately how old is the car?
The general equation for depreciation is given by y = A(1 r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years The original value of a car is $24,000 It depreciates 15% annually What is its value in 4 years?Other time period) The amount y of such a quantity after t years can be modeled by one of these equations Exponential Growth Model Exponential Decay Model y = a(1 r)t y = a(1 − r)t Note that a is the initial amount and r is the percent increase or decrease written as a decimal The quantity 1 r is the growth factor, and 1 − r is theX(t) = x 0 × (1 r) t x(t) is the value at time t x 0 is the initial value at time t=0 r is the growth rate when r>0 or decay rate when r
👍 Correct answer to the question The general equation for depreciation is given by y = a(1 – r)t, where y = current value, a = original cost, r = rate of depreciation, and t = time, in years the original value of a car is $24,000 it deprecia eeduanswerscom(1 r ) is the growth factor, r is the growth rate The percent of increase is 100 r y = C (1 r ) t 21 E XPONENTIAL D ECAY M ODEL C is the initial amount t is the time period (1 – r ) is the decay factor, r is the decay rate The percent of decrease is 100 r y = C (1 – r ) tQuestion An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The value of a car is half what it originally cost The rate of depreciation is 10% Approximately how old is the car?
Solve for t A=P(1r/n)^(nt) Rewrite the equation as Divide each term by and simplify Tap for more steps Divide each term in by Cancel the common factor of Tap for more steps Cancel the common factor Divide by Take the natural logarithm of both sides of the equation to remove the variable from the exponentX(t) = x 0 × (1 r) t x(t) is the value at time t x 0 is the initial value at time t=0 r is the growth rate when r>0 or decay rate when rWarmup y = a(1r)t 10) 00(1 003)1 = $60 11) 0(1 003)10 = $ 12) 600(1 007)4 =$ 13) 1500(1 004)8 = $5285
Rewrite y=a (2)^1/3 in the form y=a (1r)^t or y=a (1r)^t then state the growth or decay rate Mathematics, 0500 NewKidnewlessonsThe decay factor is b = 1 r In this situation x is the number of halflives If one halflife is 5730 years then the number of halflives after 500 years is x = 500 5730 y = ?Using the growth formula we have y = a(1 r) x where a = 1 (we start with 1 bacteria), and r = 100%, since the amount doubles y = 1(1 100) x = 2 x (same result) Notice that the graph is a scatter plot You cannot have a fractional part of a bacteria The dotted line is the exponential function which contains the scatter plots (the model)
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history👍 Correct answer to the question Rewrite the function in the form y=a(1r)^t of y=a(1r)^t Then state the growth of or decay rate Y=a(8)^t/2 eeduanswerscomThe figure above is an example of exponential decay In fact, it is the graph of the exponential function y = 05 x The general form of an exponential function is y = ab xTherefore, when y = 05 x, a = 1 and b = 05 The following table shows some points that you could have used to graph this exponential decay
The decay factor is b = 1 r In this situation x is the number of halflives If one halflife is 5730 years then the number of halflives after 500 years is x = 500 5730 y = ?Correct answers 2 question Use the properties of exponents to rewrite y=3e^06t in the form y=a(1r)^t or y=a(1r)^t round the value or r to the nearest thousandth then find the percent rate of change to the nearest tenth of a percent rewritten function the percent decrease is %P = C (1 r) t Continuous Compound Interest When interest is compounded continually (ie n > ), the compound interest equation takes the form P = C e rt Demonstration of Various Compounding The following table shows the final principal (P), after t = 1 year, of an account initially with C = $, at 6% interest rate, with the given
Growth model y = a(1 r)t must be modifi ed for compound interest problems Finding the Balance in an Account You deposit $9000 in an account that pays 146% annual interestAn equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The value of a car is half what it originally cost The rate of depreciation is 10% Approximately how old is the car?A)33 years B)50 years C)56 years D)66 years
Y = a(1 r)t time growth factor initial amount fi nal amount rate of decay (in decimal form) y = a(1 − r)t time decay factor Practice Check your answers at BigIdeasMathcom Rewrite the function to determine whether it represents exponential growth or exponential decay Then find the percent rate of change 1 y = 80(085)2t 2 y = 67(113)t/4 3 y = 5 ( 3— 2) −8tRemaining grams a = 16 Starting value r = 50% = 05 Decimal form b = 1 05 Decay Factor x = 500 5730 No of Half livesQuadraticFunctionsDay1writtennotebook May 14, 13 Need calculator, graph paper, writing utensil Warmup y = a(1r)t 10) 00(1 003)1 = $60 11) 0(1 003)10 = $ 12) 600(1 007)4 =$ 13) 1500(1 004)8 = $5285
Y = a(05) t/x represents the amount y of a substance remaining after t years, where a is the initial amount and x is the length of the halflife (in years) Plutonium238 Halflife years a A scientist is studying a 3gram sample Write a function that represents the amount y ofThe function is of the form y=a(1 r)t, where 1 r> 1, so it represents exponential growth Use the growth factor 1 rto fi nd the rate of growth 1 r= 107 Write an equation Solve for r= 007 r So, the function represents exponential growth and the rate of growth is 7%Answer to An equation for the depreciation of a car is given by y = A(1 r)^{t}, where y = current value of the car, A = original cost, r = rate
A L I F I Y A ' S A R T, Mumbai, Maharashtra 239 likes · 1 talking about this Art Logo Design Illustrations Packaging Branding Typography Geometry UI/UX Mural Design CommunicationP = C (1 r) t Continuous Compound Interest When interest is compounded continually (ie n > ), the compound interest equation takes the form P = C e rt Demonstration of Various Compounding The following table shows the final principal (P), after t = 1 year, of an account initially with C = $, at 6% interest rate, with the givenThe general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years A car was purchased 6 years ago for $25,000 If the annual depreciation rate is 11%, which equation can be used to determine the approximate current value of the car?
Y = a(1 r) x Remember that the original exponential formula was y = ab x You will notice that in these new growth and decay functions, the b value (growth factor) has been replaced either by (1 r) or by (1 r) The growth "rate" (r) is determined as b = 1 r The decay "rate" (r) is determined as b = 1 rIdk This equals y = *(14) t By the way the number 4 is 40%2)Find the curvature of r(t) = 9t, t 2, t 3 (9, 1, 1) at the point κ = 3)Use this theorem to find the curvature r(t) = 6t i 4 sin(t) j 4 cos(t) k κ(t) =
What is the hourly growth rate in the growth formula y=a(1r)^t Answer by nerdybill(7384) (Show Source) You can put this solution on YOUR website!The general equation for depreciation is given by y= A(1−r)t y = A (1 − r) t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years A car was purchased 6An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The value of a car is half what it originally cost The rate of depreciation is 10% Approximately how old is the car?
Suppose y(t) = tr, we have y (t) = rtr−1 and y00(t) = r(r − 1)tr−2 Thus t2y00(t) ty0(t) 9y(t) = (r(r − 1) r 9)tr = (r2 9)tr Thus y = tr is a solution of t2y00(t)αty0(t)βy(t) = 0 if r2 9 = 0 The roots of r2 9 = 0 are 3i and −3i Note that t = elnt and t3i = ei3lnt = cos(3lnt) isin(3lnt) Therefore the generalT y = a(1 r) Exponential Decay Occurs when a quantity _____ by the same rate over time t t = ExamplesExamples 7 The population of a town is decreasing at a rate of 1% per year In 00 there were 1300 people Write an exponential decay function to model this situation Then, find the populationFV = PV(1 i) n R ( (1 i) n 1 ) / i where i = r/m is the interest paid each period and n = m × t is the total number of periods Numerical Example You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly
Y = a ( 1 r k) k t, where k is the number of times the interest is compounded per year So, plugging in your information gives y = 3750 ( 1 06 12) 132 = $ Share answered Jan 15 '15 at 129 onetoinfinity onetoinfinity 435 2An equation for the depreciation of a car is given by y = A (1 – r)t, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years The current value of aY = a(1r)t Example 3 Exponential Decay 3a) A fully inflated child's raft for a pool is losing 66% of its air every day The raft originally contained 4500 cubic inches of air Write an equation to represent the loss of air Estimate the amount of air in the raft after 7 days
In a labatory, a culture increases from 30 to 195 organisms in 5 hours What is the hourly growth rate in the growth formula y=a(1r)^t y=a(1r)^t The problem gives us y as 195
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